A person spends Rs. 501 in buying tables and chairs. If the cost of each chair is Rs. 15 and table costs 40% more than the chair and total number of articles he bought was 27, how many of each kind did he buy?

• Let Chairs is represented by "C"
  and, Tables is represented by "T"
  Then, C+T=72.......(1)
  Cost of each chair(given)Rs.15
  Cost of each table is:Rs.21(given that it is 40%more)
  Then the equation becomes:
  15C+21T=501..................(2)
  Now, solve the equation
  T comes to 16 and C comes to 11
  Thus, he buys 16 tables and 11 chairs.
  
• 12 years agoHelpfull: Yes(0) No(3)
• PRT/100=225
  p=1125
  T=4
  R=5%
• 12 years agoHelpfull: Yes(0) No(0)
• answer :: 16 chair and 11 table
  
  soln:
  Let no. of Chairs be "x"
  no. of Tables be "y"
  total eqn1:: x+y=27
  
  Cost of each chair Rs.15
  Cost of each table Rs.21(15+ 40% of 15)
  eq2:: 15x+21y=501
  solving eq1 and eq 2
  y = 11 (no. of tables)
  x = 16 (no. of chairs)
  Thus, he buys 16 tables and 11 chairs.
• 12 years agoHelpfull: Yes(0) No(0)
• 11 chairs 16 tables
  each table costs 15+40*15/100=21
  15x+21y=501
  x+y=27
  by solving these two x=11,y=16
• 12 years agoHelpfull: Yes(0) No(0)