AA AB BC CE ??
a)EG b)EH c)EI d)None

• AA AB BC CE
  bcs a=1,b=2,c=3,e=5
  seq... 11,12,23,35
  add 1st and 2nd term will get 3rd term and so on
  next term will be 58 => EH
• 12 years agoHelpfull: Yes(33) No(0)
• => AA AB BC CE
  => a=1,b=2,c=3,e=5
  => seq... 11,12,23,35
  add 1st and 2nd term will get 3rd term and so on
  next term will be 58 => EH
• 12 years agoHelpfull: Yes(4) No(1)
• ans: b)EH becoz a=1,b=2 as we substitute values for this we get 11,12,23,35,?..
  add the previous 2 unit place to get that unit place and add previous 2 tens place to get that tens place... 11,12,1+1 1+2(23),1+2 2+3(35),2+3 3+5(58)
  5=E and 8=H, so answer is EH.
• 12 years agoHelpfull: Yes(2) No(1)
• AA AB BC CE
  bcs a=1,b=2,c=3,e=5
  seq... 11,12,23,35
  add 1st and 2nd term will get 3rd term and so on
  next term will be 58 => EH
• 12 years agoHelpfull: Yes(2) No(1)
• b)EH
  AA=1-1=0
  AB=|1-2|=1
  BC=|2-3|=1
  CE=|3-5|=2
  SO THE SERIES 0,1,1,2 IS A FIBONACCI SERIES WHOSE NEXT TERM IS 3..
  SINCE THE NEXT TERM MUST BEGIN WITH E IT WILL BE EH BECAUSE
  EH=|5-8|=3
• 10 years agoHelpfull: Yes(1) No(0)
• EF is the answer coz end of the first term is the beginning of the next term
• 10 years agoHelpfull: Yes(0) No(3)