Q. There are 76 persons. 54 can read Hindu, 43 can read Times, 37 can read Deccan and 15 can read all. If 24 can read Hindu and Deccan and 27 can read Deccan and Times then what is the number of persons who read only Times and Hindu.

• Let 'A'can be read Hindu,
  Let 'B'can be read Times,
  Let 'C'can be read Deccan,
  From the given data:n(AuBuC)=76,n(A)=54,n(B)=43,n(C)=37,n(AnBnC)=15,n(AnC)=24,n(BnC)=27,n(AnB)=?
  n(AuBuC)= n(A)+n(B)+n(C)-n(AnB)-n(BnC)-n(AnC)+n(AnBnC)
  ==> 76=54+43+37-n(AnB)-24-27+15
  ==> n(AnB)= 54+43+37+15-24-27-76
  ==> n(AnB)= 149-127
  ==> n(AnB)= 22
• 12 years agoHelpfull: Yes(35) No(5)
• Let, A for hindu
  B for times
  c for Deccan
  so
  N(A u B u C)= N(A) + N(B) + N(C) - N(A n B) - N(B n C) - N(C n A) + N(A n B n C)
  76 = 54 + 43 + 37 - N(A n B) - 24 -27 + 15
  N(A n B) = 22
  for only times and hindu,req.ans is ,N(A n B)-N(A n B n C)=22-15=7
• 12 years agoHelpfull: Yes(10) No(0)
• Let, A for hindu
  B for times
  c for Deccan
  so
  N(A u B u C)= N(A) + N(B) + N(C) - N(A n B) - N(B n C) - N(C n A) + N(A n B n C)
  76 = 54 + 43 + 37 - N(A n B) - 24 -27 + 15
  N(A n B) = 22
• 12 years agoHelpfull: Yes(6) No(5)
• 22
  76=76+54+43+37+15-24-27=x
  
• 10 years agoHelpfull: Yes(3) No(0)