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Maths Puzzle
The third and tenth terms of a geometric sequence are 9 and 19683 respectively. Which term of the sequence is 59,049?
Read Solution (Total 2)
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- 1*3^2=9
1*3^9=19683
1*3^10=59049
Ans= 11th term - 12 years agoHelpfull: Yes(1) No(0)
- ar^2 = 9
ar^9= 19683
divide eq 2 by eq1
r^7= 2187
r=3
so 19683*3 = 59049 , hence its 11th term - 12 years agoHelpfull: Yes(0) No(0)
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