What will be the value of x^(1/2).x^(1/4).x^(1/8)............to infinty.
1- x^2
2-x
3- x^(3/2)
4- x^3

• x^(1/2+1/4+1/8.infinite )so x^(1/2(1+1/2+1/4+.....))
  =x^(1/2(1/(1-1/2))....................infinite terms formula a/1-r for a+ar+.....
  =x^1
  =x
  
• 9 years agoHelpfull: Yes(8) No(0)
• bloody @niroshkumar dont give f**k answers x^0=1 ,, (any thing)^0=1
• 9 years agoHelpfull: Yes(2) No(0)
• x
  the owers are in gp then sum of the terms is (1/2)/(1-1/2)=1
• 9 years agoHelpfull: Yes(2) No(1)
• The term is x ^ (1/2 + 1/4 + 1/8 + ...). Sum of infinite series with first term 1/2 and common ratio of 1/2 is 1. So answer is 'x'.
  
• 9 years agoHelpfull: Yes(1) No(0)
• the ans is x
• 9 years agoHelpfull: Yes(1) No(0)
• x^(1/2+1/4+1/8+.........................)
  formula for infinite series is (a/1-r)
  = x^(0.5/1-0.5)............................we take {1/2=0.5}
  =x^(0.5/0.5)
  =x
• 9 years agoHelpfull: Yes(1) No(0)
• x^(1/2+1/4+1/8=0.86...)......infinite so x^0=x
  Ans is x
• 9 years agoHelpfull: Yes(0) No(7)
• 2-x as x^(1/2+1/4+1/8......) forming gp so a=1/2 & r=1/2
  1/2(1-1/2^infity)/(1-1/2)=1
  X^1.
• 7 years agoHelpfull: Yes(0) No(0)