By Walking at ¾ of his normal speed, Mike is 16 minutes late in reaching his office. The usual time taken by him to cover the distance between his home and his office is ?

a. 48 minutes
b. 60 minutes
c. 42 minutes
d. 62 minutes

• new speed =3/4 of usual speed
  
  new time =4/3 of usual time
  
  hence,
  
  4/3 of usual time - usual time =16
  
  hence usual time to cover that distance would be 16 *3 =48 min
• 10 years agoHelpfull: Yes(59) No(4)
• let us consider s as initial speed which reaches to office in t min, when we take 3/4*s it take( t+16)min then s*t=3/4*s*(t+16)
  t=48min
• 10 years agoHelpfull: Yes(19) No(0)
• Let Total time be x
  
  (x *3/4)+16 = x
  
  x = 64 Then
  
  Usual Time= 64 -16 = 48
  
• 10 years agoHelpfull: Yes(10) No(0)
• x*t=(3/4)x*(t+16)
  t=48 min
• 10 years agoHelpfull: Yes(7) No(0)
• The speed is 3/4.
  Then the time is 4/3
  Remaining time-(4/3-1)=1/3
  Then the speed is 3*16=48
  
• 10 years agoHelpfull: Yes(5) No(0)
• as distance is constant
  therefore s1*t1=s2*t2
  where s1 is his normal speed let it be =x
  t1 be=t
  s2=3x/4
  t2=t+16(as it take 16 min more)
  now s1*t1=s2*t2
  x*t=3x/4(t+16)
  t=48 min
• 10 years agoHelpfull: Yes(4) No(0)
• look in this problem distance is same so speed and time are inversely proportional .
  so, s1/s2=t2/t1,
  x/(3/4x)= (t+16)/t
  4t=3t+48
  
  t=48 ans
• 10 years agoHelpfull: Yes(3) No(0)
• Let Total time be x
  
  (x *3/4)+16 = x
  
  x = 64 Then
  
  Usual Time= 64 -16 = 48
  
• 10 years agoHelpfull: Yes(1) No(0)
• speed ratios is 4:3 and then time ratio si 3 : 4 so difference is 1 and time differeces is 16 min so multiply 16 by 3 and then 16 by 4 so answer is 48 : 64 so answer is 48 i.e usual speed
• 10 years agoHelpfull: Yes(1) No(0)
• let 1{m/min} be its normal speed.
  3/4 of its normal speed =3/4*1=3/4.
  therefore,
  d=st or t=d/s
  so, let x be the distance to his office from his home.
  therefore, time =time
  x/(3/4)=16+(x/1)
  (4x/3)-x=16
  x/3=16
  x/1=48
  48 min is answer as (x/1) is usual time taken..
• 10 years agoHelpfull: Yes(1) No(0)
• ans will 48
  
• 10 years agoHelpfull: Yes(0) No(3)
• here speed is in fractions i.e,, 3/4 so difference is 1. time 16.
  so you calculate time/ speed difference=16/1=16
  usual time=numerator*(time/diff)=3*16=48
  simple techinque for calculate actual time
• 10 years agoHelpfull: Yes(0) No(0)
• Ratio of speeds = 4:3
  Ratio of time = 3:4 = 48:64
  
  a. 48 minutes
• 9 years agoHelpfull: Yes(0) No(0)
• Let the initial speed of Mike be "s" and time be "t". As said in question 3/4 of his original speed and initial speed is ( 3/4*s) with that time is also taken as (t+16) is taken to find the,
  => s*t=3/4*s*(t=16) by cancelling s on both the sides
  => 4t=3t+48
  => t=48
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• let T (min) be the usual time, then he spent 4 T/3
  when walking in 3/4 of usual speed.
  Since 4T/3 = T +20, we obtain T = 60 min.
• 9 years agoHelpfull: Yes(0) No(1)
• Ans is a.
  let his usual speed is x and time take to cover this distance is t.
  now,
  xt=3x(t+16)/4
  :. t=48.
  so. right answer is a. 48.
• 9 years agoHelpfull: Yes(0) No(0)
• speed is inversely proportional to time
  1/3/4=x/x+16
  4/3=x+16/x
  3x+48=4x
  x=48 min
• 9 years agoHelpfull: Yes(0) No(0)
• d/((3/4)*x)-d/x=16
  d/x(4/3-1)=16
  d/x=16*3
  d/x=48
  d/x is usual time taken by mike
• 9 years agoHelpfull: Yes(0) No(0)
• let ,distance=d meter, total time=t min, new speed=3*d/4*t meter/min now time=(t+16)
  (3*d)/(4*t)= d/(t+16)
  t=48 min
  
• 8 years agoHelpfull: Yes(0) No(0)
• Assume initial speed = 1
  new speed =3/4
  speed ratios are in the ratio= 1 : 3/4 ==> 4:3
  time ratio= 3: 4 ( time =1/speed)
  difference between 3 & 4 is 1
  given difference is 16
  let 1p=16
  3 is actually time then 3*16=48
• 8 years agoHelpfull: Yes(0) No(0)
• s*t=3/4[s]*[t+16]
  solve it u will get 48 mins
• 8 years agoHelpfull: Yes(0) No(0)
• a.48mins
• 7 years agoHelpfull: Yes(0) No(0)
• 4/3 of usual time = Usual time + 16 minutes;
  Hence, 1/3rd of usual time = 16 minutes;
  Thus, Usual time = 16*3 = 48 minutes.
• 6 years agoHelpfull: Yes(0) No(0)
• We know that speed and time are inversely proportional so if speed decreases time will increase so therefore
  new time=4/3 times of initial time ie
  4/3(x)-x=16
  x/3=16
  x=48 minutes
• 4 years agoHelpfull: Yes(0) No(0)