1!+2!+3!+...........+50! = ?

• hey can u plz tell me are questions really repetated in tcs ???
• 13 years agoHelpfull: Yes(38) No(8)
• multiply numerator and denominator by n(n+1)/2=50*51/2=25*51
  thus u'll get (1*1!+2*2!+3*3!+4*4!+....+49*49!+50*50!)/(25*51)
  =((2-1)*1!+(3-1)*2!+(4-1)*3!+.....+(51-1)*50!)/(25*51)
  =(2!-1!+3!-2!+4!-3!+...+51!-50!)/(25*51)
  =(51!-1!)/25*51
  =2*49!-1/(25*51) [ans]
  
• 13 years agoHelpfull: Yes(20) No(32)
• 3.04*10^64
• 13 years agoHelpfull: Yes(13) No(13)
• 50P50=3.04140932*10^62
• 13 years agoHelpfull: Yes(4) No(22)
• 1.22*10^63
• 13 years agoHelpfull: Yes(1) No(12)
• 3 is the answer
  
• 9 years agoHelpfull: Yes(0) No(0)