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1!+2!+3!+...........+50! = ?
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- hey can u plz tell me are questions really repetated in tcs ???
- 14 years agoHelpfull: Yes(38) No(8)
- multiply numerator and denominator by n(n+1)/2=50*51/2=25*51
thus u'll get (1*1!+2*2!+3*3!+4*4!+....+49*49!+50*50!)/(25*51)
=((2-1)*1!+(3-1)*2!+(4-1)*3!+.....+(51-1)*50!)/(25*51)
=(2!-1!+3!-2!+4!-3!+...+51!-50!)/(25*51)
=(51!-1!)/25*51
=2*49!-1/(25*51) [ans]
- 14 years agoHelpfull: Yes(20) No(32)
- 3.04*10^64
- 14 years agoHelpfull: Yes(13) No(13)
- 50P50=3.04140932*10^62
- 14 years agoHelpfull: Yes(4) No(22)
- 1.22*10^63
- 14 years agoHelpfull: Yes(1) No(12)
- 3 is the answer
- 10 years agoHelpfull: Yes(0) No(0)
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