A railway track runs parallel to a road until a bend brings
the road to a level crossing. A cyclist rides along to work along the
road every day at a constant speed of 13 miles per hour. He normally
meets a train that travels in the same direction at the crossing. One
day he was late by 20 minutes and met the train 7 miles ahead of the level crossing. Can you figure out the speed of the train?

• If 63.375 mph is not correct , then u can give correct solution .
• 12 years agoHelpfull: Yes(2) No(0)
• 63,375 mph
  
  Man meets train 7 miles ahead from normal meeting point where he reaches 160/13 minutes before normal meeting time.
  
  So train will cover 13 miles in 160/13 minutes.
  so speed of train = 13*13*60/160 mph = 63.375 mph
• 12 years agoHelpfull: Yes(1) No(2)
• @ Pargat,
  
  63.375 mph is correct. But in your previous submission u post 63,375 mph (sixty three thousand three hundred and seventy five). That why i react like that. ok?
• 12 years agoHelpfull: Yes(1) No(1)
• 63,375 miles per hour???????? Oh my god!!
• 12 years agoHelpfull: Yes(0) No(1)
• @ Vignesh,
  You are free to react in any way you like.
  But it is better if you read the solution also if you have any doubt.
• 12 years agoHelpfull: Yes(0) No(0)
• ans is 35mph
• 10 years agoHelpfull: Yes(0) No(0)
• the speed of the train is 72 mph
• 10 years agoHelpfull: Yes(0) No(0)
• Since train has covered 7 miles in 20 minutes answer should be
  7*60/20 = 21mph
  please correct me if I am wrong
  thanks in advance
• 8 years agoHelpfull: Yes(0) No(0)