If a person moves 15km straight and turns 45 km right and moves 15Km staright then how much distance he

needs to walk to reach starting point??

• First refer to the 3rd diagram in the link:
  http://writer.zoho.com/public/suchandra/ques
  The red lines shows the path the person took. Now we can easily construct a right angled triangle as shown in the fig.By Pythagoras rule, its root of(45^2+30^2)= 54.08
• 14 years agoHelpfull: Yes(63) No(11)
• straight=15km,and right turn =45+15=60,
  distance to the starting point = square root (15^2 + 60^2)=square root (3825)=61.85
  
• 14 years agoHelpfull: Yes(34) No(31)
• assuming last 15km straight to be in similar direction with respect to the the initial straight direction.
  thus he is totally 15+15=30 km away in the same direction from his initial point.
  this makes the view of a triangle of base=45,edge1=30 then edge2=?
  now edge2^2=edge1^2+base^2=30^2+45^2=sqrt(2925)
• 14 years agoHelpfull: Yes(19) No(2)
• lets assign co-ordinates .so its starting from say(0,0). then going to the point(0,15).then to the right ay(45,15). then again straight to(45, 30). now find the distance of the points (0,0) and (45,30).its coming 54.08 km.
• 14 years agoHelpfull: Yes(12) No(6)
• by right angle triangle property
  (45+15)^2+15^2=(hypotnuese)^2
  hypotnuese=sqrt 3825
  =62.08
  answer=62.08=shortest distance between the starting and finishing point
• 12 years agoHelpfull: Yes(7) No(0)
• guys i used Pythagoras theorem---> 30^2+45^2=a^2.
  so we get a=54.08...is this the right one??????????
• 12 years agoHelpfull: Yes(2) No(2)
• Correct Answer Is 2*sqrt((15^2)+((45/2)^2))..
• 14 years agoHelpfull: Yes(1) No(8)
• ans is 30...becoz 1st go north
  then go east
  then go north again so distance is 15+15=30
• 13 years agoHelpfull: Yes(1) No(7)
• 50 take pythogors theorm
• 14 years agoHelpfull: Yes(0) No(5)