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Maths Puzzle
if a is a real non-zero real no. and b is positive real no.
2ba^4 + ba^3 + a^2 + ba + 2b = ka^2
least possible value of k??????
1.2b+1
2.2b-1.
3.2-33b/4.
4.2+33b/4.
Read Solution (Total 1)
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- 2ba^4 + ba^3 + a^2 + ba + 2b = ka^2
2ba^4 + ba^3 + a^2(1-k) + ba + 2b = 0
a^4 + (a^3)/2 + a^2(1-k)/2b + a/2 = 0
For min value of k,
(1-k)/2b = -1
k-1 =2b
k=2b+1 ..... option 1
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