CAT
Exam
A circular disc of diameter 9 cm is cut in the center and a circular hole is generated. If the weight of the disc is reduced by one third, then the diameter of the hole is:
(1)14.3 cm
(2)13.5 cm
(3)12.4 cm
(4)None of the above
Read Solution (Total 3)
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- None of these
as size /dia of hole can not be more than size of disc. - 12 years agoHelpfull: Yes(4) No(0)
- If r is radius of hole, then
(Pi*r^2)/(pi*(9/2)^2) =1/3
r^2 = (81/4)/3 = 27/4
r= (3 Root 3)/2
diameter of hole = 3 root 3= 3*1.732 = 5.196 cms
none of these. - 12 years agoHelpfull: Yes(3) No(2)
- Please check this statement.
- 12 years agoHelpfull: Yes(1) No(1)
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