what is the distance between z and x intersect in ax+by+cz=d

• At the z-intercept, 'x' and 'y' are both zero.
  cz + d = 0 --> z = -d/c --> The z-intercept is the point (0, 0, -d/c).
  At the x-intercept, 'y' and 'z' are zero.
  ax + d = 0 --> x = -d/a --> The x-intercept is the point (-d/a, 0, 0).
  The distance between the points (0, 0, -d/c) and (-d/a, 0, 0) is
  sqrt[ (-d/a)2 + (-d/c)2 ] = sqrt (d2/a2 + d2/c2) = d sqrt(1/a2 + 1/c2)
• 12 years agoHelpfull: Yes(20) No(1)
• D/C-A/C
• 12 years agoHelpfull: Yes(3) No(2)
• x-intersect=A(d/a,0,0)
  z-intersect=C(0,0,d/c)
  hence,AC=root{(d/a-0)2+(0-0)2+(0-d/c)2}=root(d2/a2+d2/c2)ans.
  where a2=a*a,d2=d*d,and so on.
• 12 years agoHelpfull: Yes(2) No(1)
• distance between z and x intersect in ax+by+cz=d
  will be
  (d/ac)*sq root ( c^2 - a^2)
• 12 years agoHelpfull: Yes(1) No(5)