A ball is dropped from a height of 15 feet.Every time it rebounces to half of the height. how many feet it travelled?

• 45 ft till it stops at ground.
  
  total distance travelled = 15 + 7.5 +7.5+ ......+0.= 15+2*((7.5/(1-1/2))=15+30 = 45 ft.
• 12 years agoHelpfull: Yes(5) No(3)
• initially ball travels 15feet.
  next, it bounces half of the height (i.e 7.5) , so from ground 7.5 up and 7.5 down , totally 15 .
  next, similary 7.5.
  the series would be 15,7.5,3.75,......
  this series is in G.P , so a=15 r=1/2
  sum = a/(1-r) = 15/(1-1/2) = 30.
  so , the answer is 15+30 =45. (here, 15 is initially ball traveled from top to ground).
• 10 years agoHelpfull: Yes(0) No(0)
• Distance travelled by ball=15+15*(1/2)+15*(1/2)**2+15*(1/2)**3+......
  
  =15*(1+(1/2)+(1/2)**2+(1/2)**3+.....)
  =15*(1/(1-1/2))
  =15*2
  =30
• 5 years agoHelpfull: Yes(0) No(0)
• Acrually it forms a submation equation
  Sub(n=1, n= ∞) {(15/n)+ (15/n+1)}
  By solving this we will get our ans
• 5 years agoHelpfull: Yes(0) No(0)