A man sold a product for rs.56 and gained x% .Its original cost is Rs. x ,what is the cost(x)?

• CP is Rs 40.
  
  x+ x*x/100 = 56
  x*(100+x) =5600
  
  solving it, x=40
• 12 years agoHelpfull: Yes(1) No(1)
• C.P. + GAIN% OF C.P.= S.P.
  NOW, C.P.= X
  GAIN= X% OF X i.e. X*X/100
  S.P.= Rs. 56
  
  Now equating
  x + x*x/100= 56
  100x + x^2= 5600
  x^2 + 100x-5600=0
  
  Now solve for x...
  
  We get x=40.
  So Rs. 40 is the answer.
  
• 12 years agoHelpfull: Yes(1) No(1)
• Ans:-cp=40
  sp=56/-
  cp=x
  g%=x%
  G%=sp-cp/cp*100
  x=56-x/x*100
  By solving this equation we can get x=40 &x=-140
  take +ve valuex=40
• 12 years agoHelpfull: Yes(0) No(2)
• ((56-x)/x).100=x
  solve it we get x=40
• 12 years agoHelpfull: Yes(0) No(1)
• Cost Price= x
  
  Gain= x% of x i.e. x*x/100
  
  Selling Price = Rs. 56
  
  So
  x + x*x/100= 56
  => 100x + x^2 = 5600
  => x^2 + 100x - 5600 = 0
  => (x+140)(x-40) = 0
  => x = -140 or x = 40.
  But cost price cannot be negative, so x = 40
• 12 years agoHelpfull: Yes(0) No(0)