How many digits are there in (3PQR)^4 where 3PQR is a 4 digit number

• 3000^4 = 27 000 000 000 000 ----- 14 digits( min)
  3999^4 = 255 744 095 984 001..... 15 digits ( max)
• 12 years agoHelpfull: Yes(4) No(4)
• If 3PQR is 4 digit number means,
  
  Maximum 4 digits = 9999
  So, 9999^4 = 9996000599960001(16 digits)
  
  Minimum 4 digits = 1000
  So, 1000^4 = 1000000000000(13 digits)
  
  So, Maximum = 16 digits
  and Minimum = 13 digits.
• 12 years agoHelpfull: Yes(3) No(2)
• @ Vignesh,
  
  U r right. but no of digits will not change.
• 12 years agoHelpfull: Yes(2) No(0)
• $ Mr. Pargat
  
  3000 ^ 4 is not 27 000 000 000 000.
  
  It is,
  
  3000^ 4 = 81 000 000 000 000(14 digits).
• 12 years agoHelpfull: Yes(1) No(1)
• Maximum digits = 16
  Minimum digits = 13
• 12 years agoHelpfull: Yes(0) No(2)
• 13
  because for each power the no is incremented by (digit of initial no-1).so,in this case for power 2 it will be(4+3)=7,then for power 3 it will be(7+3)=10 and for power 4 it will be(10+3)=13
• 12 years agoHelpfull: Yes(0) No(1)