By adding some consecutive numbers we get 2000.. What are all the numbers??

How many Possibles are there?

• 2 possible sets.
  
  398 +399+400+401+402 = 2000
  
  and
  68+69+.....+80+81 +........92 = 2000
• 12 years agoHelpfull: Yes(2) No(0)
• I think PPS is right if only positive numbers are considered.
• 12 years agoHelpfull: Yes(1) No(0)
• If negative numbers are also allowed, then
  
  one more set is possible.
  
  It will contain 125 numbers with middle number as 16.
  
  then three (3) possible sets are
  
  (-46)+(-45)+..........+0+1+2......+15+16+17+.................+78 = 2000
  
  398 +399+400+401+402 = 2000
  
  and
  68+69+.....+80+81 +........92 = 2000
  
• 12 years agoHelpfull: Yes(1) No(0)
• 13
  because for each power the no of digit increments by(no.of initial digit-1) i.e. 3(4-1)=3 in this case.so,for power 2 no of digit (4+3)=7,for power 3 it is (7+3)=10,for power 4 it is(10+3)=13
  
• 12 years agoHelpfull: Yes(0) No(3)