an examination paper consists of 8 questions of which 4 have 3 possible answers each,3 have 2 possible answers each and the remaining one question has 5 answers.the total number of possible answers to all the questions is

• 3*3*3*3 *2*2*2*5 = 81*8*5 = 81*40= 3240 possible answers
• 12 years agoHelpfull: Yes(24) No(9)
• 23 possible answers.
  
  First four questions have 12 possible answers.(Each have 3 possible answer =3*4)
  Next three questions have 06 possible answers.(Each have 2 possible answer =2*3)
  Last one have 05 possible answers. (It have 5 possible answers)
  
  So, (3*4)+(2*3)+(1*5) = 12+6+5 = 23 possible answers.
• 12 years agoHelpfull: Yes(14) No(15)
• 3^4*2^3*5^1=3240
  
• 10 years agoHelpfull: Yes(10) No(5)
• 23 possible answers totally i think????
• 12 years agoHelpfull: Yes(9) No(6)
• Possible ways to solve first = 4*3
  Possible ways to solve second = 3*2
  Possible ways to solve third = 1*5
  total ways = 12+6+5
• 9 years agoHelpfull: Yes(5) No(4)
• 4*3=12
  3*2=6
  1*5=5
  12+6+5=23
• 9 years agoHelpfull: Yes(0) No(0)