Adi leave the house at 9:30 AM daily to reach his office at 10:30 AM. He travels by his bike at a speed of 36 KMPH. One a particular day, he left home at the usual time but his bike broke down after travelling some distance, After waiting for 15 min he walked to the office at a speed of 18 KMPH and reached the office at 11 AM. Find the distance for which Adi had to walk.

• Adi had to walk 9kms.
  
  He left home at 9.30AM. And travel by bike for 27kms.(i.e., 36km/hr)
  
  That means till 10.15A.M he travel by bike. Then bike broke down.
  
  And wait for 15min (i.e)till 10.30A.M.
  
  Then he cover balance 9km by walk at speed of 18km/hr.
  
  And reach office at 11AM
• 12 years agoHelpfull: Yes(3) No(5)
• He took (30-15=15) minutes extra while walking as compared to bike ride.
  
  If x is the distance covered while walking, then
  x/18 - x/36 = 15/60=1/4
  x/36 =1/4
  x= 9 kms
• 12 years agoHelpfull: Yes(2) No(3)
• Adi had to walk 9km's.
• 12 years agoHelpfull: Yes(1) No(3)
• Ans. Adi had to walk 9 kms.
  
  Solution:
  Adi reaches office in one hours on bike at a speed of 36 KMPH. So the distance of office from his house is 36 Kms. On the day when his bike broke down let he travelled x km by bike and (36-x)km by walking. He had also waited for 15 minutes and reaches office at 11 AM. So he reached office in 3/2 hrs on that day.
  He travelled by bike for x/36 hrs.
  He walked for (36-x)/18 hrs.
  He waited for 15/60=1/4 hrs.
  So x/36 +(36-x)/18 + 1/4 = 3/2
  => x = 27
  So Adi covered distance of 27 kms by bike and 36-27 = 9 kms by walking.
  Time taken to cover 9 kms by walking at 18 KMPH = 1/2 hrs. = 90 minutes.
• 12 years agoHelpfull: Yes(0) No(2)