a^2+b^2+c^2+d^2=85^2

then find out a,b,c,d

• a^2+b^2+c^2+d^2=85^2
  
  a=3
  b=4
  c=12
  D=84
  
  3^2+4^2+12^2+84^2=85^2 =7225
• 12 years agoHelpfull: Yes(2) No(1)
• 
  
  Many solutions are possible.
  ( As vignesh has already said)
  a^2+b^2+c^2+d^2=85^2 =7225
  80^2+20^2+20^2+5^2=85^2
• 12 years agoHelpfull: Yes(2) No(1)
• It have too many possibilities.
  
  One of the possibility are,
  
  a=84, b=13,c=0,d=0
  
  a^2 + b^2 + c^2 + d^2 = 85^2
  84^2 + 13^2 + 0^2 + 0^2 = 7225
  7056 + 169 +0 + 0 = 7225
• 12 years agoHelpfull: Yes(1) No(2)
• Then it must be
  
  a=84, b=12,c=4,d=3
  
  a^2 + b^2 + c^2 + d^2 = 85^2
  84^2 + 12^2 + 4^2 + 3^2 = 7225
  7056 + 144 + 16 + 9 = 7225
• 12 years agoHelpfull: Yes(1) No(2)
• a^2+b^2+c^2+d^2=85^2
  
  80^2 +25^2 +10^2+10^2 = 7225 = 85^2
• 12 years agoHelpfull: Yes(1) No(1)
• u cant use zero single or more times thats the condition ..........
• 12 years agoHelpfull: Yes(0) No(0)
• yup right 1ce again both of u ....congrets....
• 12 years agoHelpfull: Yes(0) No(0)