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Maths Puzzle
Expand the series a little further: (t-a)(t-b)...(t-t)...(t-z) = ?
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- Answer is Zero.
Here by expanding (t-a)(t-b)..(t-t)...(t-z), we get [(t-t)=0].
Therefore, whole expression would be Zero.
i.e., (t-a)(t-b)(t-c)....(t-s)(0)..(t-z)=0 - 12 years agoHelpfull: Yes(1) No(1)
- (t-a)(t-b)...(t-t)...(t-z) =(t-a)(t-b)...*0*...(t-z) = 0
as t-t =0 - 12 years agoHelpfull: Yes(1) No(1)
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