There are 5 burglars and once went to a bakery to rob it obviously. The first guy ate 1/2 of the total bread and 1/2 of the bread. The second guy ate 1/2 of the remaining and 1/2 of the bread. The third guy ,fourth guy and fifth guy did the same. After fifth guy there is no bread left out. How many bread are there?

• First we create a general rule for amount of bread left when each burglar leaves
  Lets assume we have x no of bread
  At every step x/2 + 1/2 bread is eaten by the burglar
  Therefore after each step compared to previous step we have [x-(x/2 + 1/2)] = x/2 - 1/2 bread left.
  
  Now let us go to the problem
  Now after 5th burglar leaves we have 0 bread left
  Hence number of bread after 4th burglar leaves (or before 5th burglar enters) is calculated by
  x/2 - 1/2 = 0
  Therefore x = 1
  
  Similarly after 4th burglar leaves we have 1 bread left
  Hence number of bread after 3th burglar leaves (or before 4th burglar enters) is calculated by
  x/2 - 1/2 = 1
  Therefore x = 3
  
  Similarly after 3rd burglar leaves we have 3 bread left
  Hence number of bread after 2nd burglar leaves (or before 3rd burglar enters) is calculated by
  x/2 - 1/2 = 3
  Therefore x = 7
  
  Similarly after 2nd burglar leaves we have 7 bread left
  Hence number of bread after 1st burglar leaves (or before 2nd burglar enters) is calculated by
  x/2 - 1/2 = 7
  Therefore x = 15
  
  Similarly after 1st burglar leaves we have 15 bread left
  Hence number of bread before 1st burglar enters is calculated by
  x/2 - 1/2 = 15
  Therefore x = 31·····························Ans
  
  
• 10 years agoHelpfull: Yes(4) No(0)
• 31
• 15 years agoHelpfull: Yes(1) No(1)
• 31
• 15 years agoHelpfull: Yes(1) No(1)
• 31
• 15 years agoHelpfull: Yes(0) No(2)
• (1/2 + 1/2) = 1
  2(1 + 1/2) = 3
  2(3 + 1/2) = 7
  2(7 + 1/2) = 15
  2(15 + 1/2) = 31
• 7 years agoHelpfull: Yes(0) No(0)