on dividing a number by 56 ,we get 29 as remainder.on dividing the same number by 17 ,what will be the remainder
a)4 b)5 c)6 d)7

• b)5
  
  number is 56x+29
  when x=1, number is 85 which is fully divisible by 17. remainder 0.
  when x=2, number is 112+29= 141 when divided by 17, we get 8 as quotient and 5 as remainder.
  
  so remainder can be 5 from given options.
• 12 years agoHelpfull: Yes(7) No(4)
• There is no constant remainders for this.
  
  Eg:
  
  When we divide a number 85 by 56, we get remainder 29. But when we divide the same number 85 by 17, we get remainder 0.
  
  Like that,When we divide a number 141 by 56, we get remainder 29. But when we divide the same number 141 by 17, we get remainder 5.
  
  Like that, When we divide a number 197 by 56, we get remainder 29. But when we divide the same number 197 by 17, we get remainder 10.
  
  So, remainder may differ in every cases.
  
  
• 12 years agoHelpfull: Yes(4) No(3)
• b) 5 is the remainder
  
  Dividing number by 56, we get 29 as remainder means,
  
  Original number we divide by 56 is = 56+29 = 85
  
  So, When dividing 85 by 17, we get remainder 5.
• 12 years agoHelpfull: Yes(2) No(4)
• Sorry I post a wrong answer.
• 12 years agoHelpfull: Yes(0) No(2)
• ANS. B 5
  SOLUTION:-
  DIVIDEND =QUOTIENT *DIVISOR + REMAINDER
  Let quotient is 1.
  DIVIDEND =1*56 +29 = 85
  85 DIVIDED BY 8 THEN QUOTIENT IS 10 AND REMAINDER IS 5.
• 9 years agoHelpfull: Yes(0) No(0)
• 56(divisor)*x(quotient)+29(remainder)=dividend
  
  so we can see clearly
  56x+29=required number
  if x=1 then number=85,if divide 85 with 56 we get 29 as remainder
  dividing 85 with 17 we will get 0 as remainder
• 7 years agoHelpfull: Yes(0) No(0)