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Maths Puzzle
on dividing a number by 56 ,we get 29 as remainder.on dividing the same number by 17 ,what will be the remainder
a)4 b)5 c)6 d)7
Read Solution (Total 6)
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- b)5
number is 56x+29
when x=1, number is 85 which is fully divisible by 17. remainder 0.
when x=2, number is 112+29= 141 when divided by 17, we get 8 as quotient and 5 as remainder.
so remainder can be 5 from given options. - 12 years agoHelpfull: Yes(7) No(4)
- There is no constant remainders for this.
Eg:
When we divide a number 85 by 56, we get remainder 29. But when we divide the same number 85 by 17, we get remainder 0.
Like that,When we divide a number 141 by 56, we get remainder 29. But when we divide the same number 141 by 17, we get remainder 5.
Like that, When we divide a number 197 by 56, we get remainder 29. But when we divide the same number 197 by 17, we get remainder 10.
So, remainder may differ in every cases.
- 12 years agoHelpfull: Yes(4) No(3)
- b) 5 is the remainder
Dividing number by 56, we get 29 as remainder means,
Original number we divide by 56 is = 56+29 = 85
So, When dividing 85 by 17, we get remainder 5. - 12 years agoHelpfull: Yes(2) No(4)
- Sorry I post a wrong answer.
- 12 years agoHelpfull: Yes(0) No(2)
- ANS. B 5
SOLUTION:-
DIVIDEND =QUOTIENT *DIVISOR + REMAINDER
Let quotient is 1.
DIVIDEND =1*56 +29 = 85
85 DIVIDED BY 8 THEN QUOTIENT IS 10 AND REMAINDER IS 5. - 10 years agoHelpfull: Yes(0) No(0)
- 56(divisor)*x(quotient)+29(remainder)=dividend
so we can see clearly
56x+29=required number
if x=1 then number=85,if divide 85 with 56 we get 29 as remainder
dividing 85 with 17 we will get 0 as remainder - 7 years agoHelpfull: Yes(0) No(0)
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