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Q1. Six friends decide to share a big cake. Since all of them like the cake, they begin quarreling who gets to first cut and have a piece of the cake. One friend suggests that they have a blindfold friend choose from well shuffled set of cards numbered one to six. You check and find that this method works as it should simulating a fair throw of a die. You check by performing multiple simultaneous trials of picking the cards blindfold and throwing a die. You note that the number shown by the method of picking up a card and throwing a real world die, sums to a number between 2 and 12. Which total would be likely to appear more often – 8,9 or 10?
a) 8 b) All are equally likely c) 9 d) 10
Read Solution (Total 3)
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- in a series of events the probability of the most likely to be happend is the median.
here the median is (12+2)/2=7
now for those given numbers the maximum probability of occurring will b the nearest to this median.
thus 8 is the nearest 1.. so the ans is 8 :) - 14 years agoHelpfull: Yes(21) No(2)
- First Look At The Options.. Then Decide The Correct Answer.
8 Will Appear (2+6),(3+5),(4+4)...In 3 Ways..
9 Will Appear (5+4),(6+3)...In 2 Ways.
10 Will Appear (5+5),(4+6)...In 2 Ways.
So The Answer Is 8.. - 14 years agoHelpfull: Yes(16) No(1)
- 8
- 14 years agoHelpfull: Yes(5) No(7)
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