In a stable there are men and horses. In all, there are 22 heads and 72 feet. How many men and how many horses are in the stable

• there will be 14 horses and 8 men
  14*4=56 feet
  8*2=16 feet
  56+16=72
• 12 years agoHelpfull: Yes(5) No(0)
• Total 72 feet and 22 heads
  There are 8 men and 14 horses now we can verify our solution 14*4=56 and 8*2=16
  the total feet = 16+56=72
• 12 years agoHelpfull: Yes(4) No(0)
• Let the no. of horses be : h
  Let the no. of men be : m
  both will be having one head only
  eq1 : h+m = 22
  now horses will be having 4 legs and man will be having 2 legs,
  eq2 : 4h+2m = 72
  by solving eq 1 and 2 ::
  HORSES(h) = 14 MEN (m) = 8 (answer)
• 12 years agoHelpfull: Yes(4) No(0)
• 14 horses & 8 mens are there. (14+8=22 heads), (14*4=56)+(8*2=16)=72
• 12 years agoHelpfull: Yes(1) No(1)
• x+y=22;
  4x+2Y=72;
  x=14;y=8;
  14*4+8*2=56+16=72
  
• 9 years agoHelpfull: Yes(0) No(0)
• If, A --> men and B --> horsesSo, A + B = 22 and 2A + 4B = 722 (22 - B) + 4 B = 7244 - 2 B + 4 B = 7244 + 2 B = 722 B = 72 - 44 = 28B = 14 (horses)So, there are in the stable 8 men and 14 horses.
• 9 years agoHelpfull: Yes(0) No(0)
• If, A --> men and B --> horsesSo, A + B = 22 and 2A + 4B = 722 (22 - B) + 4 B = 7244 - 2 B + 4 B = 7244 + 2 B = 722 B = 72 - 44 = 28B = 14 (horses)So, there are in the stable 8 men and 14 horses.
• 9 years agoHelpfull: Yes(0) No(0)
• If, A --> men and B --> horsesSo, A + B = 22 and 2A + 4B = 722 (22 - B) + 4 B = 7244 - 2 B + 4 B = 7244 + 2 B = 722 B = 72 - 44 = 28B = 14 (horses)So, there are in the stable 8 men and 14 horses.
• 9 years agoHelpfull: Yes(0) No(0)