There were 60 players playing a game among themselves. Each player is out of the game when lose 3 matches. What is the number of matches should be played in order to get the winner.

• since there are 60 players 1 should be the winner and 59 players are losers
  Each player is eliminated only if he lost in 3 games therefore total no. of games are 59*3=177
• 12 years agoHelpfull: Yes(11) No(1)
• Max number of matches to be played in order to get the winner = 3*60 -1= 179
• 12 years agoHelpfull: Yes(8) No(10)
• if 1 player get eliminated from 3 match , when second last will eliminate the match will be 180-3 =177 , the last will be the player so no further playing is reuired
• 5 years agoHelpfull: Yes(1) No(0)
• pargat pal singh sir pls will you explain the solution of this sum
• 12 years agoHelpfull: Yes(0) No(1)
• @sabnam your answer is correct.
  @pargat ji u r considering 2 extra matches, as winner will not going to play the game with himself.
• 12 years agoHelpfull: Yes(0) No(2)
• no.of players=60
  no.of winner=1
  no.of player's eliminated=60-1=59
  no.of matches to be lost for eliminating a player=3
  total rounds required=3x59=177
  Answer is 177.
• 4 years agoHelpfull: Yes(0) No(0)