complete the series:
3, 35, 99, 195, 323,___, ___

• 3, 35, 99, 195, 323,___, ___
  3, 35, 99, 195, 323, 483,675
  
  35=3+32
  99= 35+2*32
  195=99+3*32
  ..
  ..
  323+32*5= 483
  483+32*6 = 675
• 12 years agoHelpfull: Yes(5) No(1)
• 483, 675
  
  Final series = 3, 35, 99, 195, 323, 483, 675
  
  Series increasing like
  
  3 + (32*1) = 35
  35+ (32*2) = 99
  99+ (32*3) = 195
  195+(32*4) = 323
  323+(32*5) = 483
  483+(32*6) = 675
• 12 years agoHelpfull: Yes(1) No(4)
• Ans. The final series is :
  3, 35, 99, 195, 323, 483,675
  
  Explanation:
  The terms of the series are
  A(1) = 3
  and
  A(n) = A(n-1)+ 32*(n-1) for n >= 2
  A(6)= A(5)+32*5 = 323 + 160 = 483
  A(7)= A(6)+32*6 = 483 + 192 = 675
• 12 years agoHelpfull: Yes(0) No(1)