value of (2^n+2^(n-1))/(2^(n+1)-2^n) is:

• 3/2
  
  
  (2^n+2^(n-1))/(2^(n+1)-2^n) = (2^(n-1)*(2+1))/((2^n )*(2-1)) =3/2
• 12 years agoHelpfull: Yes(13) No(2)
• take n=1
  (2^1+2^(1-1))/(2^(1+1)-2^1)
  (2+1)/(4-2)=3/2
• 12 years agoHelpfull: Yes(8) No(4)
• 2^(n-1)(2+1)/2^n(2-1)=3/2=1.5
• 12 years agoHelpfull: Yes(2) No(0)
• (2^n+2^(n-1))/(2^(n+1)-2^n)=[2^n(2^(-1)+1)]/[2^n(2-1)]
  =[2^(-1)+1]/1 (2^n gets cancelled)
  =3/2
• 12 years agoHelpfull: Yes(2) No(0)
• sol:: [2^(n-1)*(2+1)]/[2^n*(2-1)]
  => [2^(n-1-n)*3]
  => [2^(-1)*3]
  => [3/2]
  => 1.5 (answer)
• 12 years agoHelpfull: Yes(1) No(2)
• (2^n+2^(n+1))/(2^(n+1)-2^n)
  = 2^n+2^n-1/2^n+1-2^n
  =3/2
• 12 years agoHelpfull: Yes(0) No(0)
• we can write it as
  ->(2^n+((2^n)/2))/((2^n)*2-2^n)
  ->(2^n(1+(1/2)))/(2^n(2-1))(2^n gets cancelled in numerator and denominator)
  ->(1+(1/2))/(1)=3/2
• 12 years agoHelpfull: Yes(0) No(0)
• (2^n+2^(n-1))/(2^(n+1)-2^n)
  =( 2^n (1+1/2) )/ ( 2^n (2-1) )
  =(1 + 1/2)/(2-1)
  =(3/2)/1
  =3/2
• 12 years agoHelpfull: Yes(0) No(0)
• answer is 1.5
  (2^n(1+0.5))/(2^n(2-1))
  =1.5/1
• 12 years agoHelpfull: Yes(0) No(0)
• 2^(n-1)(2+1)/2^(n-1)(2^2-2)=3/2.
• 12 years agoHelpfull: Yes(0) No(0)
• 3/2.
  2^n(1+2^-1)/2^n(2-1)=1+1/2=3/2
• 12 years agoHelpfull: Yes(0) No(0)