Can you find the values of integers a, b, c so that a/b + b/c + c/a an integer.
where a# b#c
means a,b,c are not equal to each other.

• Having Lot of Possibilities.
  
  One of those are,
  
  a = 4; b = 8; c = 2;
  Therefore,
  
  => (a/b)+(b/c)+(c/a) = (4/8)+(8/2)+((2/4)
  => 0.5 + 4 + 0.5
  => 5
  All are integers.
• 12 years agoHelpfull: Yes(3) No(1)
• Possibles of a,b,c are
  
  a=4; b=8; c=2;==>(a/b)+(b/c)+(c/a) = (4/8)+(8/2)+(2/4) ==> 0.5 + 4 + 0.5 ==> 5
  
  a=8; b=2; c=4;==>(a/b)+(b/c)+(c/a) = (8/2)+(2/4)+(4/8) ==> 4 + 0.5 + 0.5 ==> 5
  
  a=2; b=4; c=8;==>(a/b)+(b/c)+(c/a) = (2/4)+(4/8)+(8/2) ==> 0.5 + 0.5 + 4 ==> 5
  
  All values of a,b,c and answer will be integers.
• 12 years agoHelpfull: Yes(3) No(1)
• Possible Values can be calculated by following eqn.
  
  If, a = x; b = 2(x); c = 2(b); Or
  If, b = x; c = 2(x); a = 2(c); Or
  If, c = x; a = 2(x); b = 2(a);
  
  By Putting x= any integer except 0, we find so many possibilities of values.
• 12 years agoHelpfull: Yes(2) No(0)
• a=1,b=2,c=4
  (a/b)+(b/c)+(c/a)=(1/2)+(2/4)+(4/1)=0.5+0.5+4=5
• 12 years agoHelpfull: Yes(1) No(0)