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Maths Puzzle
12, 32, 70, 132, 224, ___
Read Solution (Total 8)
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- Ans. 352
Explanation:
The nth terms of the series is = (n+1)^3 + (n+3)
(1+1)^3 + (1+3) = 12
(2+1)^3 + (2+3) = 32
(3+1)^3 + (3+3) = 70
(4+1)^3 + (4+3) = 132
(5+1)^3 + (5+3) = 224
(6+1)^3 + (6+3) = 352
- 12 years agoHelpfull: Yes(2) No(0)
- 12 32 70 132 224 ____ is 362
diff 20 38 62 92 so 138
again 18 24 30 should be 36
answer:362 - 12 years agoHelpfull: Yes(1) No(2)
- ans:352
explanation:(2pow3+4)=12,(3pow3+5)=32,(4pow3+6)=70,(5pow3+7)=132,(6pow3+8)=224,(7pow3+9)=352 - 12 years agoHelpfull: Yes(1) No(0)
- 352.mutual differences
12
20
32 18
38 6
70 24
62 6
132 30
92 6
224 36
128
352 - 12 years agoHelpfull: Yes(1) No(0)
- 12 + 20 = 32
32 + 38 = 70 ( 20 + 18 = 38)
70 + 62 = 132 ( 38 + 24 = 62)
132 + 92 = 224 ( 62 + 30 = 92)
224 + 128 = 352 ( 92 + 36 = 128)
352 + 170 = 522 ( 128 + 42 = 170)
522 + 218 = 740 ( 170 + 48 = 218) - 12 years agoHelpfull: Yes(0) No(0)
- 2*2*3=12,
2*4*4=32,
2*7*5=70,
2*11*6=132,
2*16*7=224,
2*22*8=352,
2*29*9=522 and so on - 12 years agoHelpfull: Yes(0) No(1)
- 352
2^3+4=12
3^3+5=32
4^3+6=70
5^3+7=132
6^3+8=224
7^3+9=352 - 12 years agoHelpfull: Yes(0) No(0)
- 12 -32=20
32-70=38
70-132=62
132-224=92 - 7 years agoHelpfull: Yes(0) No(0)
self Other Question
If a person have coins of only two denominations (among 5,20,25,50 paisa),in such a way that if quantity of one denomination is multiplied by its value and again multiplied by 4, it's equal to the amount obtained when other denomination coin is multiplied by its value. Find these two types of coins.
3,11,31,69,131,___, ___