Ritu was asked to multiply a two-digit number N by a three-digit number M. But she mistakenly multiplied N by the number formed by writing the digits of M in the reverse order, thereby getting an answer which was 22770 more than the correct answer.

1) Find the correct product of N and M, if it is known that had Ritu reversed the digits of both the numbers N and M, she would have got an answer 12816 more than her earlier answer.
A. 9982
B. 13284
C. 32752
D. 45568
E. 13842

2) What is the minimum possible sum of the digits of M?
A. 8
B. 11
C. 6
D. 5
E. 7

• N = 46 ; M = 217 ;
  
  1) Find the correct product of N and M,
  Ans = A)9982
  
  2) What is the minimum possible sum of the digits of M?
  Ans = According to option, ans is A)8. (i.e, 1+7 =8)
  
  Explanation:
  
  ==> N * M = 46 * 217 = 9982
  ==> mistakenly multiplied N by the number formed by writing the digits of M in the reverse order, thereby getting an answer which was 22770 more than the correct answer.
  
  46 * 712 = 32752 (i.e, 9982 + 22770 = 32752)
  
  ==> Ritu reversed the digits of both the numbers N and M, she would have got an answer 12816 more than her earlier answer.
  
  64 * 712 = 45568 (i.e, 32752 + 12816 = 45568)
• 12 years agoHelpfull: Yes(1) No(6)
• check at
  http://www.pagalguy.com/forum/quantitative-questions-and-answers/80436-official-quant-thread-cat-2012-a-205.html
• 12 years agoHelpfull: Yes(1) No(0)