self Maths Puzzle

The below is a number puzzle. It should be read left to right, top to bottom.

1
1 1
2 1
1 2 1 1
1 1 1 2 2 1
? ? ? ? ? ?
? ? ? ? ? ? ? ?

Question 1: What is the next two rows of numbers?
Question 2: How was this reached?

Read Solution (Total 2)

Next Two numbers are,
3 1 2 2 1 1
1 3 1 1 2 2 2 1

It reached as,
1
1 1 (In previous sequence we have [One 1's (i.e, 1 1)])
2 1 (In previous sequence we have [Two 1's(i.e, 2 1)])
1 2 1 1(In previous sequence we have [One 2's, One 1's (i.e, 1 2 1 1)])
1 1 1 2 2 1(In previous sequence we have [ One 1, One 2, Two 1's (i.e, 1 1 1 2 2 1)])

Like that, next will be
3 1 2 2 1 1 (Previous seqn we have [Three 1's, Two 2's, One 1's]-->3 1 2 2 1 1
1 3 1 1 2 2 2 1 (Previous seqn we have [One 3, One 1's, Two 2's, Two 1's])
12 years agoHelpfull: Yes(3) No(0)

QUESTION 1:312211
2:13112221
EXPLANATION:count number of 1's,2's,3's and represents as above
12 years agoHelpfull: Yes(0) No(1)

self Other Question

-20= -20
16-36 = 25- 45
4^2 - 9*4 = 5^2 - 9*5
Adding 81/4 on both sides
4^2 - 9*4 + 81/4= 5^2 - 9*5 + 81/4
4^2 - 5*9 + (9/2)^2 = 5^2 -5*9 + (9/2)^2

Now substituting the formula( a-b)^2 we get 4-9/2 = 5-9/2
» 4=5
Or 2+2 = 5
I want to know where we are wrong????
How can you throw a ball as hard as you can and have it come back to you, even if it doesn't bounce off anything? There is nothing attached to it, and no one else catches or throws it back to you.