There is a 5digit no. 3 pairs of sum is eleven each. Last digit is 3 times the first one. 3 rd digit is 3 less than the second.4 th digit is 4 more than the second one. Find the digit.

• 25296
  Let the 5 digit no be: a b c d e
  last digit is 3 times first: e=3a
  3rd digit less than second: c=b-3
  4th digit is 4 more than second: d=4+b
  
  now a,b,b-3,4+b,3a
  3pairs of sum is 11
  therefore
  a+b=11--------eqn1
  b-3+b+4=11----eqn2
  
  
  
  
• 12 years agoHelpfull: Yes(16) No(18)
• 25296 which satisfy all the conditions.
  
  3 pairs of sum is eleven = (2,9)(2,9)(5,6)
• 12 years agoHelpfull: Yes(13) No(8)
• Let the require number be d1d2d3d4d5
  Given d5=3d1
  d3=d2-3
  d4=d2+4
  since sum of pair of digits=11
  consider d3+d4=11
  d2-3+d2+4=11
  => d2=5
  d3=d2-3
  d3=5-3
  d3=2
  
  d4=d2+4=5+4
  d4=9
  hence require number = __529__
  here 9+2=11
  now we have think of a number which should be added to five to get 11
  5+6=11
  hence the last number is 6
  since d5=3d1
  ∴d1=2
  hence the ans is 25296
• 9 years agoHelpfull: Yes(6) No(0)
• 25296
  Let the 5 digit no be: a b c d e
  last digit is 3 times first: e=3a
  3rd digit less than second: c=b-3
  4th digit is 4 more than second: d=4+b
  
  now a,b,b-3,4+b,3a
  3pairs of sum is 11
  therefore
  a+b=11--------eqn1
  b-3+b+4=11----eqn2
  
  so ans is 25296
• 9 years agoHelpfull: Yes(0) No(1)