What is the probability of getting the sum 5 in two throws of the dice?

a. 1/12 b. 1/5 c. 1/9 d. None of these

• c. 1/9 is the probability of getting the sum 5 in two throws of dice.
  
  In two throws of a die, n(S) = (6 * 6) = 36.
  Let E = event of getting a sum, n(E) ={(1, 4), (2, 3), (3, 2), (4, 1)}.
  
  P(E)= n(E)/n(S)
  =4/36
  =1/9
• 12 years agoHelpfull: Yes(29) No(4)
• Answer is 1/9(c)
  throwing two dice sum 5 comes in (1,4) (2,3) (3,2) (4,1)
  probability= 4/36 = 1/9
  36 is no.of throws
• 10 years agoHelpfull: Yes(3) No(0)
• (1,4) (2,3) (3,2) (4,1) are the possibilities on getting sum 5 on throwing 2 dice
  Probability= 4/36 = 1/9
  where 36 is the sample space
• 10 years agoHelpfull: Yes(2) No(1)