Pick 3 digits (not zero) and make 6 2-digit numbers from them. Add up all these numbers, add up all the original digits and divide the first total by the second.

• let numbers be a,b,c.
  In the 6 two digit numbers ,ab,ac,ba,bc,ca,cb we have a total of2*(a+b+c) ones and 2*(a+b+c) tens . their sum is 20(a+b+c)+2(a+b+c)=22(a+b+c).dividing this sum by(a+b+c) we get 22 as answer.
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