The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?

• Let the digits of the number are x & y.
  by hypothesis, 10x+y-(10y+x)=36,
  =>x-y=4---->(1),
  And x:y=1:2 (or) y:x=1:2.
  If x:y=1:2, digits are negative.
  So, y:x=1:2----->(2),
  From (1)&(2), x=8 & y=4.
  Therefore the difference between the sum and the difference of the digits of the number = (x+y)-(x-y)=2y=2*4=8.
• 14 years agoHelpfull: Yes(19) No(0)
• let A be 10's digit and B be ones
  so
  10A+B - (10B+A)=36
  A-B=4
  ALSO A:B OR B:A=1:2
  SO A=8 AND B=4
  SO ANS. IS 3:1
  
• 14 years agoHelpfull: Yes(2) No(2)
• The number is 48 difference = 12-4 = 8
  reverse is 84
  diff=36
  ratio is 1:2
• 14 years agoHelpfull: Yes(2) No(2)
• If The difference between a two digit number and the number obtained by
  interchanging the position of the digits of the number is 9 then "Differnce between the digits of that number" is 1.., as well as...
  * for 18 -> 2
  * for 27 -> 3
  * for 36 -> 4
  ....... * for 72 -> 8..
  I think this is the best solution for such type of questions..
• 11 years agoHelpfull: Yes(0) No(1)