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Value of (1+3+5....+3983)/1992 ?
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- 1992
sum of AP = (n/2)*(a+l)
(1+3+5....+3983)
here n= (1+3983)/2= 3984/2 = 1992
a=1, l=3983
(1+3+5....+3983) = (1992/2)*(1+3983)= 3984*1992/2
(1+3+5....+3983)/1992 = (3984*1992)/(2*1992)= 3984/2=1992 - 12 years agoHelpfull: Yes(3) No(1)
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