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Maths Puzzle
Numerical Ability
Permutation and Combination
A number when divided by 8,7,6,5 leaves a remainder 1,2,3,4. find the number ?
a)3208 b)3209 c)3334 d)3210
Read Solution (Total 2)
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- 3209
Number will be 8x+1
From given options
only 3209 satisfies this condition.
Otherwise start from last point
If last quotient is 1 then previous quotient = 5*1+4 =9
Earlier quotient = 6*9+3 =57
earlier quotient = 7*57+2 = 401
Initial number = 8*401 +1= 3209 - 12 years agoHelpfull: Yes(7) No(10)
- ans=3209 it is so simple i think u dont need soln;
- 7 years agoHelpfull: Yes(0) No(4)
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