given
carpenter + painter = 1100
painter + electrician = 3200
electrician + plumber = 5100
plumber + mason = 2200
mason + labour = 3000
labour + painter = 1100
find every person's cash?

• Given Cash details is wrong.
  
  Because,
  Assume, Carpenter = C; Painter = P; Electrician = E; Plumber = A; Mason = M; Labour = L;
  
  C+P=1100
  P+E=3200
  E+A=5100
  A+M=2200
  M+L=3000
  L+P=1100
  
  Here, E involves in two.
  
  P+E = 3200
  E+A = 5100
  
  Assume that E=3200(Max value in P+E). That means,
  E+A = 5100 -->3200+A=5100 -->3200+1900 = 5100 (This implies, A=1900)
  
  So, if A=1900,
  A+M = 2200 -->1900+M = 2200 -->1900+300 = 2200 (This implies, M=300)
  
  So, If M=300,
  M+L = 3000 -->300+L = 3000 -->300+2700 = 3000 (This implies, L=2700)
  
  So, if L=2700,
  L+P = 1100 --> 3000+p = 1100?????????
  
  Its not possible that Painter cash will be go in minus.
  
  So, given datas are wrong..
• 12 years agoHelpfull: Yes(2) No(2)
• subtracting the equations
  
  carpenter-painter=0
  carpenter=painter=550
  electrician=3200-550=2650
  plumber=5100-2650=2450
  mason=2200-2450 not possible
  
• 12 years agoHelpfull: Yes(0) No(0)