A finish the work in 10 days. B is 60% efficient than A. So how days does B take to finish the work?

• Ans. 25/4 days
  A finishes part of work in one day = 1/10
  So B will finish part of work in one day = (1/10)*(160/100)= 4/25
  Hence B will finish work in 25/4 days.
• 12 years agoHelpfull: Yes(23) No(5)
• A finishes part of work in one day = 1/10
  So B will finish part of work in one day = (1/10)*(60/100)= 3/50
  
  so B will take 50/3 days to complete the work.
• 12 years agoHelpfull: Yes(8) No(8)
• 160 : 100=10 :x
  x=25/4
• 9 years agoHelpfull: Yes(2) No(1)
• ratio of time taken by A and B= 160 : 100 = 8 : 5
  
  suppose B alone takes x days to do the job
  
  Then, 8 : 5 :: 10 : x = 6 1/4 days
• 9 years agoHelpfull: Yes(1) No(0)
• options ..which is it ? 25/4 or something else ?
• 9 years agoHelpfull: Yes(1) No(0)
• so 10*(60/100)=6
  10-6=4
  so 4 days is the answer
• 6 years agoHelpfull: Yes(1) No(0)
• b takes 6 days
  
• 9 years agoHelpfull: Yes(0) No(0)