A person is to go up a tree 60ft high. In every second, he climbs 5ft but slips 4ft. After how many seconds, will he be able to touch the top of the tree?

• In every sec, he covers 1 ft.
  In 55 secs , he will cover , 55 ft.
  In next 56th sec, he will touch 55+5= 60 FT TOP.
  
  SO 56 Secs.
• 12 years agoHelpfull: Yes(9) No(1)
• 56 sec
  55 sec for 55 feet + 5 feet for 1sec
  56 sec
• 12 years agoHelpfull: Yes(6) No(0)
• Ans. 56 seconds.
  In one second he climbs 5ft but slips 4ft it means he covers 1 ft in one second.
  So in 55 secs , he will cover 55 ft.
  In the 56th sec, he will climb 5 ft. and he will touch the top as 55+5= 60 ft.
• 12 years agoHelpfull: Yes(4) No(0)
• ans: 60 sec
  
  because in every second he climb 5ft but slip 4ft, so he just climb 1ft in 1sec
  for 60 ft, he takes 60 sec to touch top of the tree
• 12 years agoHelpfull: Yes(3) No(4)
• in every 1 sec he will cover 1 ft
  so on 55th sec he will cover 55 ft
  and on 56th sec he willclimb up 5 ft and touch the top which is at 60 ft above
  so ans 56 sec
• 9 years agoHelpfull: Yes(1) No(0)
• 56 secs
  in 1 sec, he climbs 5 ft and slips 4 ft
  in 55 sec,he will have covered 55 ft
  in 56th sec,he climb 5 ft and 55+5=60 ft
• 4 years agoHelpfull: Yes(0) No(0)