1 Peter and Paul are two friends The sum of their ages is 35 years Peter is twice as old

let peter is now x and paul is y.
so, x+y=35
and x=2{y-(x-y)}
[think,ur age is 22(x) and ur brother is 19(y).now when ur age was 19 at that time ur brother age was {22(x)-19(y)}that is 3 less than 19;that is 19(y)-{22(x)-19(y)}]

solving two eq. x=20,y=15
13 years agoHelpfull: Yes(14) No(0)
from the option if we take 20 as Peter's age then Paul's age is (35-20)=15...when Peter's age was 15,Paul's age was 10 and twice the value of 10 is 20 which is the present age of Peter.
13 years agoHelpfull: Yes(12) No(3)
20
p=peter
pa=paul
p=2(pa+x)
x=(pa-p) so x=pa-p
p=2(pa+pa-p) -> 4pa-2p
3p=4pa -> 4(35-p)
7p=140 so p=20
13 years agoHelpfull: Yes(2) No(1)
questiion need to be verified ..i think some lines are missing
13 years agoHelpfull: Yes(1) No(14)
Let peter's age=x & paul's age=y
Given: x+y=35
Wen peter was as old as paul is now, i.e.
wen peter was y i.e.(x-y) yrs ago,
then paul was y-(x-y)=2y-x yrs old.
so, acc. to condition:
x=2* Paul's age x-y yrs ago,i.e.
x=2(2y-x)
x=4y-2x
x=4(35-x)-2x
x=140-6x
7x=140
x=20

i.e. Peter's age is 20 yrs old.
11 years agoHelpfull: Yes(0) No(0)

1. Peter and Paul are two friends. The sum of their ages is 35 years. Peter is twice as old as Paul was when Peter was as old as Paul is now. What is the present age of Peter?
a) 8 b) 20 c) 16 d) 15