In a mixture, R is 2 parts, S is 1 part. In adder to make S to 25% of the mixture, how much R is to be added?

• 1 part of R needed to add
  
• 12 years agoHelpfull: Yes(3) No(0)
• ans =3 part of r.given r=2part and s=1 part .
  let mixture is 1 liter then by that ratio the %of s=1 *100(1+2)
  s=33.3%
  now to make s=25%added the r=3 part.
• 12 years agoHelpfull: Yes(2) No(0)
• present ratio R/S=2/1
  For S to be 25%(=1),R should be 4,
  So 2 parts of R is to be added
• 12 years agoHelpfull: Yes(1) No(0)