If the positions of the digits of a two-digit number are interchanged, the number obtained is smaller than the original number by 27. If the digits of the number are in the ratio of 1:2, what is the original number?

• 63
  
  If original number=10x+y , after changing position of digits, new number=10y+x
  Given, 10x+y -27 =10y+x or 9y-9x=-27 ---(i)
  Also y/x=1/2 or x=2y ---(ii)
  From (i) & (ii), x=6, y=3
  So original number=10*6+3=63
  
• 9 years agoHelpfull: Yes(0) No(1)