TCS Company Logical Reasoning Cryptography

In a two-dimensional array, X(9,7), with each element occupying 4 bytes of memory, with the address of the first element X(1,1) is 3000, find the address of X(8,5).

Read Solution (Total 5)

Base + w[n(i-1)+(j-1)]
base=3000, w=4, m=9, n=7, i=8, j=5

therefore 3000+4(7(7)+4)
hence answer is 3212
12 years agoHelpfull: Yes(10) No(0)

The address of X(8,5)=3212
12 years agoHelpfull: Yes(1) No(3)
address=3212
12 years agoHelpfull: Yes(1) No(1)
3212 is ans
formula is base+w[n(i-1)+j-1]
3000+4*[49+4]=3212
12 years agoHelpfull: Yes(1) No(1)
can anyone explain in detail..??
10 years agoHelpfull: Yes(0) No(0)

TCS Other Question

(a) 2+6i (b)1+i (c) 6-2i (d) 1-7i
Find which of the above is orthogonal and why? Find the result of the following expression if, M denotes modulus operation, R denotes round-off, T denotes truncation: M(373,5)+R(3.4)+T(7.7)+R(5.8)