find the number of 1s in binary format of this equation
512*1024+255*64+3

• 512 , 1024, 64 = 1(No. of 1) {Any no. such as x = 2^n, will have only one 1 in binary}
  255 = 8 (No. of 1)
  3 = 2
  
  => 1*1+8*1+2
  => 11
• 9 years agoHelpfull: Yes(32) No(1)
• 1000000000*10000000000*11111111000*00000010000*11000000000.....i think 13 answer
• 9 years agoHelpfull: Yes(7) No(3)
• 11
  10000000*10000000000+0111111*100000+011
• 9 years agoHelpfull: Yes(6) No(2)
• In the Question asking no 1's in this question but peoples menuplate the equation....
  512 contain 1, 1's
  1024 contain 1, 1's
  255 contain 8 , 1's
  64 contain 1, 1's
  3 contain 2, 1's
  so total 1's in given equation is= 1+1+8+1+2=13
  so, ans will be :13
  
• 9 years agoHelpfull: Yes(3) No(4)
• 512 *1024= 2^9*2^10
  255*64 =(2^7+2^6+2^5+2^4+2^3+2^2+2^1+2^0)*2^6
  3 =2^1*2^0
  
  count total two (not power) then answer will be 11.
  
• 9 years agoHelpfull: Yes(1) No(0)
• 1000000000*10000000000+11111111*1000000+11
  =13
• 9 years agoHelpfull: Yes(1) No(1)
• 512*1024=2^9*2^10=2^19 (2^n form contains only 1 1's in binary )---> 1 1's
  any no. multiplied by 2^n does not change the no of 1's of that no. in binary
  so 255*64 has--> 8 1's
  and 3 has --> 2 1's
  answer is 1 + 8 + 2= 11
• 9 years agoHelpfull: Yes(1) No(0)
• 11 becoz 2^n has only 1 one and 255 when divided by to gives 7 one and 3 is also give 1 one
  
• 8 years agoHelpfull: Yes(0) No(0)
• correct answer=11
  when we convert 540611 into binary we get,
  10000011111111000011
  so total 1=11.
  
• 8 years agoHelpfull: Yes(0) No(0)