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A ship leaves on a long voyage. When it is 28 miles from the shore, a seaplane, whose speed is 10 times that of the ship is sent to deliver mail. How far from the shore does the seaplane catch upto with the ship?
Read Solution (Total 7)
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- 280/9 miles.
If ship speed is x mph, then plane speed = 10x mph.
relative speed = 9x mph
time taken by plane to catch ship = 28/9x
distance travelled by ship in that time = 10x*28/9 = 280/9 miles - 12 years agoHelpfull: Yes(15) No(7)
- Let the ship travels 'x' miles more,
Then the seaplane needs to travel (28+x) miles,
so we get, 28+x = 10x
9x = 28
x = 28/9 = 3.10 miles
Distance from the shore = 28 + 3.1 = 31.1 miles. - 12 years agoHelpfull: Yes(14) No(1)
- 280/9 miles as suggested by PP singh is correct.
- 12 years agoHelpfull: Yes(3) No(1)
- If ship speed is x mph, then plane speed = 10x mph.
relative speed = 9x mph
time taken by plane to catch ship = 28/9x h
distance travelled by ship in that time = x*28/9x =28/9
so,,the distance from the shore is (28+28/9)=280/9 miles - 12 years agoHelpfull: Yes(3) No(2)
- 280/9...correct ans
- 12 years agoHelpfull: Yes(0) No(1)
- 280/11... bcoz they were opposite to each other so 10x+x=11x. so 280/11x
- 11 years agoHelpfull: Yes(0) No(1)
- time taken is same for both the ships & seaplanetime =distance/speed...
.if speed of ship=s
then seaplane speed=10s
let distance of ship be x then seaplane distance =28+x
therefore (x / s = (28 + x ) / 10s)
then we get x = 28/9 therfore total distance = 28+28/9=31.1 - 10 years agoHelpfull: Yes(0) No(0)
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