Four prime numbers are given in ascending order of their magnitudes, the product of the first three is 385 and that of the last three is 1001. Find the largest of the given prime numbers

• 13
  
  two middle numbers are common in these 2 products whose product is equal to HCF of 385 and 1001.
  HCF = 77
  largest number = 1001/77 =13
  smallest number = 385/77 =5
• 12 years agoHelpfull: Yes(41) No(0)
• The prime nos are 5,7,11,13
  
  1st three no product is 385 so 5*7*11 = 385
  Last three no product is 1001 so 7*11*13 =1001
  
  four prime numbers are 5,7,11,13
  
  the largest of the given prime number is 13
• 10 years agoHelpfull: Yes(6) No(2)
• let the numbers are a,b,c and d
  abc = 385
  bcd = 1001
  abc/bcd = 385/1001 => a/d = 5/13
  => a=5 and d=13
  hence
  lowest number = 5 and
  highest number = 13
• 7 years agoHelpfull: Yes(4) No(0)
• 13
  5,7,11,13 are four prime numbers being considered here.
• 12 years agoHelpfull: Yes(2) No(2)
• 385 so 5*7*11 = 385
  1001 so 7*11*13 =1001
  four prime numbers are 5,7,11,13
  
  the largest of the given prime number is 13
  
• 10 years agoHelpfull: Yes(2) No(1)
• 11 ekrhsndkid jkuwerbkdf khdeb
• 10 years agoHelpfull: Yes(1) No(1)