(16^3)+(17^3)+(18^3)+(19^3) is devied by 35 reminder??

• zero
  a^3+b^3 = (a+b)^3 -3ab(a+b)
  
  here a+b = 16+19=35
  17+18=35
  
  so sum will be a factor of 35.
  zero remainder when sum is divided by 35.
• 12 years agoHelpfull: Yes(23) No(0)