The reminder obtained when 1! + 2! + . . . . .95! is divided by 15 is
a.14 b.3 c.1 d.None of these

• Remainder will be 3.
  1!+2!+3!+4! = 1+2+6+24 = 33 which gives 4 as remainder when divided by 15.
  
  all other terms after 4! i.e from 5!(120) onwards are multiple of 15.
• 12 years agoHelpfull: Yes(2) No(0)
• Remainder will be 3.
  1!+2!+3!+4! = 1+2+6+24 = 33 which gives 3 as remainder when divided by 15.
  
  all other terms after 4! i.e from 5!(120) onwards are multiple of 15.
• 12 years agoHelpfull: Yes(0) No(0)