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Maths Puzzle
When 7179 and 9699 are divided by another natural number N, remainder obtained is same. How many values of N will be ending with one or more than zeroes?
a.24 b.124 c.46 d.None of these
Read Solution (Total 1)
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- none of these
as 18 values are possible.
7179 = Nx+R
9699= Ny+R
N(y-x) = 2520 = (2*5)* (2^2 * 7 * 3^2)
So N can have values 3*2*3 =18 - 12 years agoHelpfull: Yes(1) No(0)
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